Question

10. Calculaţi:

a) 5. {7 + 3 · [46 +6 · (27 – 32 : 4)]}

b) (2^8)^2 : 2^2^4 · (3^2 – 1) – 3^0 · 2^2

c) (3^19·25^9)^2 : 15^36.
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Answer 1

Răspuns:

a)5 × { 7 + 3 × [ 46 + 6 × ( 27 - 32 : 4 )]}

5 × { 7 + 3 × [ 46 + 6 × ( 27 - 8 )]}

5 × { 7 + 3 × [ 46 + 6 × 19 ]}

5 × { 7 + 3 × [ 46 + 114 ]

5 × { 7 + 3 × 160 }

5 × { 7 + 480 }

5 × 487 = 2435 ;

b) ( 2⁸ )² : 2¹⁶ × ( 3² - 1 ) - 3⁰ × 2²

2¹⁶ : 2¹⁶ × ( 9 - 1 ) - 1 × 4

1 × 8 - 4

8 - 4 = 4 ;

c) ( 3¹⁹ × 25⁹ )² : 15³⁶

( 3¹⁹ × 25⁹ )² / 15³⁶

( 3¹⁰ × 3⁹ × 25⁹ )² / 15³⁶

( 3¹⁰ × [ 3 × 25 ]⁹ )² / 15³⁶

( 3¹⁰ × 75⁹ )² / 15³⁶

3²⁰ × 75¹⁸ / 5³⁶ × 3³⁶

15¹⁸ × 5¹⁸ / 5³⁶ × 3¹⁶

15¹⁸ / 5¹⁸ × 3¹⁶

3¹⁸ × 5¹⁸ / 5¹⁸ × 3¹⁶

3¹⁸ / 3¹⁶ = 3² = 9

sper că te-am ajutat :)