Question

10. Să se calculeze:
a)√8 (3√3 - 5√2) - 6(√6 – 4);
b)(6√2-11) (2√2 + 5).
c) 6√12:2√2

Answer 1

10.   a) √8(3√3-5√2)-6(√6-4)⇒3√24-5√16-6√6+24⇒6√6-20-6√6+24( 6√6 si -6√6 se anuleaza intre ei)⇒-20+24=4

       b) (6√2-11)(2√2+5)⇒12*2+30√2-22√2-55⇒24+8√2-55⇒8√2-31

       c) 6√12:2√2= 3√6