Question

{[(100+100:a-20):5+5]×4-50}×3-10+10:10=141

Answer 1

Răspuns: a = 5

Explicație pas cu pas:

{[(100+100:a-20):5+5]×4-50}×3-10+10:10=141

{[(100+100:a-20):5+5]×4-50}×3-10+1=141

{[(80+100:a):5+5]×4-50}×3-9=141

{[(80+100:a):5+5]x4-50]x3 = 141+9

{[(80+100:a):5+5]x4-50]x3 = 150

[(80+100:a):5+5]x4-50 = 150:3

[(80+100:a):5+5]x4-50= 50

[(80+100:a):5+5]x4 =50+50

[(80+100:a):5+5]x4 = 100

(80+100:a):5+5 = 100:4

(80+100:a):5+5 = 25

(80+100:a):5 =25-5

(80+100:a):5 = 20

80 + 100:a = 20 x 5

80+100:a = 100

100:a =100-80

100:a=20

a = 100:20

a= 5