Question

100 de puncte va rog rapidddd!

Answer 1

Explicație pas cu pas:

1) f(x) = ax + b

a)

f(2) = 2 => 2a + b = 2

f(3) = 3 => 3a + b = 3

3a - 2a = 3 - 2 => a = 1

2×1 + b = 2 => b = 0

=> f(x) = x

b)

f(0) = 1 => a•0 + b = 1 => b = 1

f(1) = 0 => a + 1 = 0 => a = -1

=> f(x) = -x + 1

c)

f(1/2) = 3 => a/2 + b = 3

f(-1/2) = 0 => -a/2 + b = 0

b + b = 3 + 0 <=> 2b = 3 => b = 3/2

a/2 + 3/2 = 3 <=> a + 3 = 6 => a = 3

=> f(x) = 3x + 3/2

d)

f(0) = 0 => a•0 + b = 0 => b = 0

f(1) = 5 => a + 0 = 5 => a = 5

=> f(x) = 5x

2)

a) f(x) = 3x - 5; f(0) = -5; f(5/3) = 0

b) f(x) =

c) f(x) = 5x; f(0) = 0; f(1) = 5

d) f(x) = 4

e) f(x) = √3•x - 2; f(0) = -2; f(√3) = 1

f) f(x) = -1/2

g) f(x) = (1/2)•x; f(0) = 0; f(2) = 1

h) f(x) =

i) f(x) = 4x - 1; f(0) = -1; f(1/4) = 0

j) f(x) =