Question

11,2g Fe reactioneaza cu o solutie de CuSO4. Determinati ce cantitate de Cu se depune, exprimata in grame si in moli.

Answer 1

$11,2g........................................x\\Fe + CuSO4 => FeSO4 + Cu\\56g.........................................64g\\\\x=\frac{11,2*64}{56}=12,8g$

$n=\frac{m}{M}=\frac{12,8}{64}=0,2 moli$