Question

11. calculati a (2+4+6+8+10):(1+2+3+4+5) dau coroana ​

Answer 1

(2+4+6+8+10):(1+2+3+4+5)=30:15= $=2$

SAU

$(2 + 4 + 6 + 8+10) \div (1 + 2 + 3 + 4 + 5) \\ = 2(1 + 2 + 3 + 4 +5) \div (1 + 2 + 3 + 4 + 5) \\ = 2 \times \frac{5 \times 6}{2} \div \frac{5 \times 6}{2} \\ \\ = 30 \div 15 \\ = 2$

SAU

$(2+4+6+8+10):(1+2+3+4+5) \\ =2(1+2+3+4+5):(1+2+3+4+5) \\ =2$

Answer 2

Răspuns:

(2+4+6+8+10):(1+2+3+4+5)=

30:15=

2