Question

11x3x[3+4x(15+6xa):18}=27
[(a+240:3)x5+100]:600=
{[(7-3)x5-2+3]:7+9}:a=4
Va rog e urgent! ​

Answer 1

Răspuns:

Este 1 nu 11

Explicație pas cu pas:

1x3x[3+4x(15+6xa):18]=27

3x[3+4x(15+6xa):18]=27

3+4x(15+6xa):18=27:3

4x(15+6xa):18=9-3

4x(15+6xa):18=6

4x(15+6xa)=6x18

4x(15+6xa)=108

15+6xa = 108 : 4

15+ 6xa =27

6xa = 27-15

6xa = 12

a= 12 : 6=2 deci a=2

[(a+270:3)x5+100]=600x1

[(a+90)x5+100]=600

(a+90)x5=600-100

(a+90)x5=500

(a+90)=500:5

a+90=100

a=100-90

a=10

{[(7-3)*5-2+3]:7+9}:x=4

[(4*5-2+3):7+9]:x=4

[(20-2+3):7+9]:x=4

(21:7+9):x=4

12:x=4

x=12:4

x=3