Question

12⅓:{[2¾:(1⅔+1 7/8×x)]*8/11+1⅔}=5

Answer 1

Răspuns:

Explicație pas cu pas:

Introduc intregii in fractie:

12 intregi si 1/3 = ( 12×3+1)/3 = 37/3

2 intregi si 3/4 = ( 2×4+3)/4 = 11/4

1 intreg si 2/3 = ( 1×3+2)/3 =5/3

1 intreg si 7/8 = (1×8+7)/8 = 15/8

1 intreg si 2/3 = (1×3+2)/3 = 5/3

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37/3 : { [ 11/4 : ( 5/3 + 15x/8)] × 8/11 + 5/3 } = 5

[ 11/4 : ( 5/3 + 15x/8)] × 8/11 + 5/3 = 37/3 : 5

[ 11/4 : ( 5/3 + 15x/8)] × 8/11 = 37/(3×5) - 5/3

[ 11/4 : ( 5/3 + 15x/8)] × 8/11 = 37/15 - 25/15

[ 11/4 : ( 5/3 + 15x/8)] × 8/11 = 12/15

11/4 : ( 5/3 + 15x/8) = 4/5 : 8/11

11/4 : ( 5/3 + 15x/8) = (4/5) × 11/8

11/4 : ( 5/3 + 15x/8) = 11/10

5/3 + 15x/8 = 11/4 : 11/10

5/3 + 15x/8 = 11/4 × 10/11

5/3 + 15x/8 = 5/2

15x/8 = 5/2 - 5/3

15x/8 = 15/6 - 10/6

15 x/8 = 5/6

15 x = 8 × 5/6

x = 20/3  : 15

x = ( 20/3 ) × 1/15

x = 4/9