Question

121/25*[0,(03)]²+3/4:[37/3*9/3-11/2*9/2]

Answer 1

$\frac{121}{25} \times \frac{1}{33 {}^{2} } + \frac{3}{4} \div (37 - \frac{99}{4} ) = \frac{121}{5 {}^{2} \times 3 {}^{2} \times 11 {}^{2} } + \frac{3}{4} \div ( \frac{144}{4} - \frac{99}{4} ) = \frac{1}{225} + \frac{3}{4} \div \frac{45}{4} = \frac{1}{225} + \frac{3}{4} \times \frac{4}{45} = \frac{1}{225} + \frac{1}{15} = \frac{1}{225} + \frac{15}{225} = \frac{16}{225}$
Baftă!