Question

(13/12-7/15):37/20+3 intreg2/3=

(37/30-3/4):29/30-(2intreg5/8-1intreg3/4):3 intreg1/2

va rog repe de dau coroana .....la cel care raspunde primul si tot ce vreti

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Answer 1

Răspuns:

Explicație pas cu pas:

• (13/12-7/15):37/20+3 intreg2/3=4

(195-84) / 180 * 20/37 + 11/3

111/180 * 20/37 + 11/3

2220/6660 + 11/3

(2220+24420) / 6660 = 4

• (37/30-3/4):29/30-(2intreg5/8-1intreg3/4):3 intreg1/2 = -41/16

(37/30 - 3/4 ) : 29/30 - (2 5/8 - 1 3/4 ) : 3 1/2

(148-90) / 120 * 30/29 - (21/8 - 7/4 ) * 7/2

58/120 * 30/29 - (21-14)/8 * 7/2

1/2 - 7/8 * 7/2 = 1/2 - 49/16 = (8-49) / 16 = -41/16