Question

14. Afla numárul divizorilor naturali ai numårului:


3 la puteoria 2 • 5 la puterea 4 •7
10la puterea 3 •4 la puterea 6 • 7 la puterea 4​

Answer 1

Răspuns:

3² = 3 × 3 = 9 => D9 = 1, 3, 9

5⁴ = 5× 5× 5× 5 = 625 => D625 = 1, 5, 25, 125, 625

7 = 7 => D7 = 1, 7

10³ = 10 × 10 × 10 = 2 × 5 × 2 × 5 × 2 × 5 = 1000 => D1000 = 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 200, 250, 500, 1000

4⁶ = 2¹² = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 4096 => D4096 = 1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096

7⁴ = 7 × 7 × 7 × 7 = 2401 => D2401 = 1, 7, 49, 343, 2401

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