Question

14. Efectuați produsele şi reduceți termenii asemenea:
a) (x2 + 2)(x + 3) – x²(3x + 2) + (3x2 + 2)(x + 2) - 4;
b) (x + 5)(2x - 3) - 2x(x + 4) + (x - 2)(x - 3);
c)(3x + 1)(x - 4) - 3x(x – 4) - (x + 3)(x + 4);
d) (x + 4)(2x + 5) + (2x + 3)(x + 1) - 4x(x + 2).
Dau coroană!! Urgent!! ​

Answer 1

Răspuns:

a) x³ + 7x² + 4x + 6

b) - 9 - 14x

c) - 6x - 16 - x²

d) 10x + 23

Explicație pas cu pas:

a) ( x² + 2 )( x + 3 ) - x² ( 3x + 2 ) + ( 3x² + 2 )( x + 2 ) - 4

x³ + 3x² + 2x + 6 - 3x³ - 2x² + ( 3x³ + 6x² + 2x + 4 ) - 4

x³ + 3x² + 2x + 6 - 3x³ - 2x² + 3x³ + 6x² + 2x + 4 - 4

- 2x³ + x² + 2x + 6 + 3x³ + 6x² + 2x

x³ + 7x² + 2x + 6 + 2x

x³ + 7x² + 4x + 6

b) ( x + 5 )( 2x - 3 ) - 2x ( x + 4 ) + ( x - 2 )( x - 3 )

2x² - 3x + 10x - 15 - 2x² - 8x + x² - 3x - 2x + 6

7x - 15 - 8x + x² - 5x + 6

- x - 9 - 13x = - 9 - 14x

c) ( 3x + 1 )( x - 4 ) - 3x ( x - 4 ) - ( x + 3 )( x + 4 )

3x² - 12x + x - 4 - 3x² + 12x - ( x² + 4x + 3x + 12 )

3x² - 12x + x - 4 - 3x² + 12x - x² - 4x - 3x - 12

x - 4 - x² - 7x - 12

- 6x - 16 - x²

d) ( x + 4 )( 2x + 5 ) + ( 2x + 3 )( x + 1 ) - 4x ( x +2 )

2x² + 5x + 8x + 20 + 2x² + 2x + 3x + 3 - 4x² - 8x

4x² + 13x + 20 + 5x + 3 - 4x² - 8x

18x  + 23 - 8x

10x + 23.

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