Question

14 Pentru fiecare dintre cazuri, determinați a + b + c, astfel încât:
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Answer 1

a) ab+bc+ca=77

10a+b+10b+c+10c+a=77

11a+11b+11c=77

11(a+b+c)=77

a+b+c=7

b) ab+bc+ca=121

10a+b+10b+c+10c+a=121

11a+11b+11c=121

11(a+b+c)=121

a+b+c=11

c) abc+cab+bca=444

100a+10b+c+100c+10a+b+100b+10c+a=444

111a+111b+111c=444

111(a+b+c)=444

a+b+c=4

d) ab+ac+ba+bc+ca+cb=154

10a+b+10a+c+10b+a+10b+c+10c+a+10c+b=154

22a+22b+22c=154

22(a+b+c)=154

a+b+c=7