Question

15. Calculati: b) [2 la puterea 5 – (4√3) la puterea 2]×5/12×(√6×√24-2)+7 la puterea 2;​

Answer 1

Răspuns:

[2⁵-(4√3)²]·5/12·(√6·√24-2)+7² =

[2⁵-16·3]·5/12· (√6·√4·√6-2)+7² =

[2⁵- 2⁴·3]·5/12· (6·2-2)+7² =

(2·3)·5/12·6+7² =

6·5/12·6+49 =

5/2·6+49 =

15+49 =64