Question

(16×12 la puterea 10, -4×12 cu puterea 10):12 la puterea 11

Answer 1

$\bf \big(16\cdot12^{10}-4 \cdot 12^{10} \big):12^{11}=$

$\bf 12^{10}\cdot \big(16\cdot12^{10-10}-4 \cdot 12^{10-10} \big):12^{11}=$

$\bf 12^{10}\cdot \big(16\cdot12^{0}-4 \cdot 12^{0} \big):12^{11}=$  

$\bf 12^{10}\cdot \big(16\cdot1-4 \cdot 1 \big):12^{11}=$

$\bf 12^{10}\cdot \big(16-4 \big):12^{11}=$  

$\bf 12^{10}\cdot12:12^{11}=12^{10+1}:12^{11}=$

$\bf 12^{11}:12^{11}=12^{11-11}=12^{0}=\red{\underline{1}}$

$==pav38==$