Question

16(×+3)²-9(X+2)²=?
Prin metode de descompunere in factori​

Answer 1

Răspuns:

16(x+3)²-9(x+2)²

=[4(x+3)-3(x+2)]×[4(x+3)+3(x+2)]

=(4x+12-3x-6)(4x+12+3x+6)

=(x+12-6)(4x+12+3x+6)

=(x+6)(4x+12+3x+6)

=(x+6)(7x+12+6)

=(x+6)(7x+18)