Question

17. Calculaţi: a) √3 (4+√6)-(√12 – √18) + (√27 + 2√6): √3– (√8 +3); Va rog rapid​

Answer 1

Răspuns:

$4 \sqrt{3} + 3 \sqrt{2} - 2 \sqrt{3} + 3 \sqrt{2} + (3 \sqrt{3} + 2 \sqrt{6} ) \div \sqrt{3} - 2 \sqrt{2} - 3 = 2 \sqrt{3} + 6 \sqrt{2} + 3 + 2 \sqrt{2} - 2 \sqrt{2} - 3$

$= 6 \sqrt{2} + 2 \sqrt{3} = 2(3 \sqrt{2} + \sqrt{3)}$