Question

17. Efectuați calculele: a) 6x + [2x²(3x + 5)-3x²(2x - 4)]: (2x); b) 3x - [4x³(2x + 3)-3x²(x² + 4x)]: (-5x²); c) x(x - 1) + [2x³(x+2) = x²(x² + 4x)]: x²³; d) [x(x²+x-2) − x(x − 2)]: x² + x(x − 1). lculele:​

Answer 1

Răspuns:

Răspuns:

17. a) 6x³+6x²-5x-5 totul supra 2x

b) -3x³-12x²+23x+12 totul supra 5

c) x²

d) 2x²-x

18. a) -2x²+4x+11

b) 2x²+6x+13

c) -7x²+14x-15

d) -2x²-1

Explicație pas cu pas:

17. a) 6x+(2x+3x+5-6x³+6x²)÷(-2x) =

= 6x+(5x+5-6x³+6x²)÷(-2x) =

= 6x+ 5x+5-6x³+6x²/-2x =

= 6x- 5x+5-6x³+6x²/2x =

= 12x²-(5x+5-6x³+6x²)/2x =

= 12x²-5x-5+6x³-6x²/2x =

= 6x²-5x-5+6x³/2x =

= 6x³+6x²-5x-5/2x

b) 3x-(8x²+12x-3x⁴-12x³)÷(-5x) =

= 3x+ 8x²+12x-3x⁴-12x³/5x =

= 3x+ x(8x+12-3x³-12x²)/5x =

= 3x+ 8x+12-3x³-12x²/5 =

= 15x+8x+12-3x³-12x²/5 =

= 23x+12-3x³-12x²/5 =

= -3x³-12x²+23x+12/5

c) x²-x+(2x²+4x-x²-4x)÷x =

= x²-x+x²÷x =

= x²-x+x =

= x²

d) (x³+x²-2x-x²+2x)÷x+x²-x =

= x³÷x+x²-x =

= x²+x²-x =

= 2x²-x