Question

18.Fie:a=(1+2+3,...,1995)•2:1996;b=(2^17:4^8)^1996:8^665.Calculati:2(a+b)-10^0
24.Calculati:a)[2^48:2^18+(3^4)^5+6^23:6^]-[2^10•3^10+2^17•2^13+(3^5)^4];
B)6+2•[(3•5^2-2^2•18:3^2+3•11):2^2]
C)2^3•5^2+(2^7•25•3^2):(9•4^2•5);
D)10•{18^2:324+2•[(2^2•3)^15:(2^29•3^15:(2^29•3^15)+1^24]}
E)2+2+4+8+16-2^5
F)2^74:(2^3•2^70)+(2+2•10^2):103
G)3125-5•(2+2•10^6)+6^7:(2^4•3^5)
H)2^3+2^10:2^8•2+2•2^7:2^5+2^10:(3•2^5+2^5)
I)2^3•5^2+(2^7•25•3^2):(9•4^2•5).

Answer 1

Rezolvarile in atasament. La ex f si g cred ca ai scris ceva gresit. Verifica. In viitor incearca sa pui o poza. E mai usor si pt tine si pt cel care raspunde.