Question

(18radical2-24radical3)÷6+2(4radical3-3radical2)-(30radical3+15radical2)÷5​

Answer 1

$(18 \sqrt{2} - 24 \sqrt{3} ) \div 6 + 2(4 \sqrt{3} - 3 \sqrt{2} ) - (30 \sqrt{3} + 15 \sqrt{2} )\div 5 = \frac{6(3 \sqrt{2} - 4 \sqrt{3}) }{6} + 8 \sqrt{3} - 6 \sqrt{2} - \frac{5(6 \sqrt{3} + 3 \sqrt{2}) }{5} = 3 \sqrt{2} - 4 \sqrt{3} + 8 \sqrt{3} - 6 \sqrt{2} - 6 \sqrt{3} - 3 \sqrt{2} = - 2 \sqrt{3} - 6 \sqrt{2}$