Question

2 2 2003
(10 - 8 ) :6:2+1

Answer 1

$( 10^{2} - 8^{2} ) : 6:2+ 1^{2003}$
$10^{2}$ =10
$8^{2}$ = 64
$1^{2003}$ =1
Deci : (100-64):6:2+1=36:6:2+1=6:2+1=3+1=4

Answer 2

(10²-8²):6:2+1 la puterea 2003=
(100-64):6:2+1=
36:6:2+1=
6:2+1=
3+1=
4