Question

(2+2×3)×{2×2^2×2^43-2^46+[3^148÷3^43-(3^5)^21]+16}

Answer 1

Am folosit proprietatile puterilor si am efectuat calculele.

Answer 2

( 2 + 2 × 3 ) × { 2 x 2² x 2⁴³ - 2⁴⁶ + [ 3¹⁴⁸ : 3⁴³ - ( 3⁵ )²¹ ] + 16 } = 128

= ( 2 + 6 ) x [ 2 ⁽ ¹ ⁺ ² ⁺ ⁴³ ⁾ - 2⁴⁶ + ( 3⁽ ¹⁴⁸ ⁻ ⁴³ ⁾  - 3 ⁵ ˣ ²¹  ) + 16 ] =

= 8 x [ 2⁴⁶ - 2⁴⁶ + ( 3¹⁰⁵ - 3¹⁰⁵ ) + 16 ] =

= 8 x ( 0 + 0 + 16 ) =

=8 x 16 =

= 128