Question

(2+2×3)×{2×2²×2⁴³-2⁴⁶+[3¹⁴⁸:3⁴³-(3⁵)²¹]+16}= ​

Answer 1

Răspuns :

128

Explicație pas cu pas :

(2 +2 ×3) ×[2 ×2 ^2 ×2 ^43 - 2 ^46 +3 ^148 :3 ^43 - (3 ^5) ^21] +16 =

(2 +6) ×[2 ^(1+2+43)-2 ^46 +3 ^(148-43)-3 ^(5×21)]+16 =

8 ×(2 ^46 - 2 ^46 +3 ^105 - 3 ^105) +16 =

8 ×16 =

128

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Answer 2

Răspuns: 128

Explicație pas cu pas:

Salutare!

$\bf (2+2\cdot3)\cdot\{2\cdot2^{2}\cdot 2^{43}-2^{46}+[3^{148}:3^{43}-(3^{5})^{21}]+16\}=$

$\bf 8\cdot[2^{1+2+43}-2^{46}+(3^{148-43}-3^{5\cdot21})+16]=$

$\bf 8\cdot[2^{46}-2^{46}+(3^{105}-3^{105})+16]=$

$\bf 8\cdot[2^{46}-2^{46}+(0)+16]=$

$\bf 8\cdot(0+0+16)=$

$\bf 8\cdot 16=$

$\boxed{\bf 128}$

Formule pentru puteri

a⁰ = 1    sau   1 = a⁰

(aⁿ)ᵇ = aⁿ ˣ ᵇ    sau   aⁿ ˣ ᵇ = (aⁿ)ᵇ

aⁿ · aᵇ = (a · a)ⁿ ⁺ ᵇ    sau    (a · a)ⁿ ⁺ ᵇ = aⁿ · aᵇ

aⁿ : aᵇ = (a : a)ⁿ ⁻ ᵇ    sau    (a : a)ⁿ ⁻ ᵇ = aⁿ : aᵇ

aⁿ · bⁿ = (a · b)ⁿ        sau    (a · b)ⁿ = aⁿ · bⁿ

aⁿ : bⁿ = (a : b)ⁿ        sau    (a : b)ⁿ = aⁿ : bⁿ  

#copaceibrainly