Question

х^2-22х+96=0
.............??​

Answer 1

x^2+22x+96=0

$\frac{-22+\sqrt{22^2-4\cdot \:1\cdot \:96}}{2\cdot \:1}$

$=\frac{-22+\sqrt{100}}{2\cdot \:1}$

$=\frac{-22+\sqrt{100}}{2}$

$=\frac{-22+10}{2}$

$=\frac{-12}{2}$$=-\frac{12}{2}$ $= -6$

$\frac{-22-\sqrt{22^2-4\cdot \:1\cdot \:96}}{2\cdot \:1} =$

$=\frac{-22-\sqrt{100}}{2\cdot \:1}$

$=\frac{-22-10}{2}$

$=\frac{-32}{2}$

$=-16$

$x_{1}$ = -6

$x_{2}$ =-16

Sper că te-am ajutat!

Succes!