Question

2+{2x[(2+2+2):2+2]-2}-2=8
Adevarat sau fals​

Answer 1

$2 + (2 \times ((\underline{2 + 2 + 2}) \div 2 + 2) - 2) - 2 = 8 \\ 2 + (2 \times (\underline{6 \div 2} + 2) - 2) - 2 = 8 \\ 2 + (2 \times (\underline{3 + 2}) - 2) - 2 = 8 \\ 2 + (\underline{2 \times 5 }- 2) - 2 = 8 \\ 2 + (\underline{10 - 2}) - 2 = 8 \\ \not2 + 8 - \not 2 = 8 \\ 8 = 8$

Answer 2

2+{2x[(4+2):2+2]-2}-2=8
2+[2x(6:2+2)-2]-2=8
2+[2x(3+2)-2]-2=8
2+(2x5-2)-2=8
2+(10-2)-2=8
2+8-2=8
10-2=8
8=8
Raspuns: Adevarat