Question

2×3²-3²+3×PARANTEZA PATRATA3+3×(3³-3la puterea5÷3³-3²)paranteza patrata

Answer 1

=2x9-9+3x[3+3x(27-243:27-9)]=
=2x9-9+3x[3+3x(27-9-9)]=
=2x9-9+3x[3+3x9]=
=2x9-9+3x[3+27]=
=2x9-9+3x30=
=18-9+90=
=9+90=
=99

Answer 2

2·3²-3²+3·[3+3·(3³-$3^{5}$÷3³-3²)]=
2·9-9+3·[3+3·(3³-3²-3²)]=
18-9+3·[3+3·(27-9-9)]=
18-9+3·(3+3·9)=
18-9+3·30=
18-9+90=
9+90= 99.