Question

2×(3radical2-radical3)+4×(radical3-radical2) Va rog frumos sa ma ajutati!

Answer 1

Răspuns

2 × ( 3√2 - √3 ) + 4 × ( √3 - √2 ) =

6√2 - 2√3 + 4√3 - 4√2 = 2√2 + 2√3 = 2 ( √2 + √3 )

Answer 2

Răspuns

$2\sqrt{2}+2\sqrt{3}$

Explicație pas cu pas:

=2$6\sqrt{2}-2\sqrt{3}:6\sqrt{2}-2\sqrt{3}$=

=$6\sqrt{2}-2\sqrt{3} +4(\sqrt{3}-\sqrt{2} )$

=$4(\sqrt{3} :\sqrt{2} ):4\sqrt{3} -4\sqrt{2}$=

=$6\sqrt{2}-2\sqrt{3} +4\sqrt{3} -4\sqrt{2}$=

=$6\sqrt{2}-2 \sqrt{3} +4\sqrt{3} -4\sqrt{2}:2\sqrt{2}+2\sqrt{3}$=

=$2\sqrt{2} +2\sqrt{3}$

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