Question

(2-3x)^2+(2+3x)^2-(2x-3)^2-(4x+3)(4x-3)​

Answer 1

[2^2-2•2•3x+(3x)^2 ]+ [2^2+2•2•3x+(3x)^2 ]-[(2x)^2-2•2x•3+3^2] - [ (4x)^2-3^2 ]

(4-12x+9x^2) + (4+12x+9x^2) - (4x^2 +12x-9) - (16x^2+9) (minusul din fata paranteze schimba semnul din paranteza)

Desfacem parantezele:

4 - 12x + 9x^2 + 4 + 12x + 9x^2 - 4x^2 + 12x - 9 - 16x^2 + 9

-12x se reduce cu 12x , -9 cu 9

8-2x^2