Question

2×[4×(x-0,3)-0,4]=4,8​

Answer 1

 

$\displaystyle\bf\\2\times[4\times(x-0,\!3)-0,\!4]=4,\!8~~~\Big|~:2\\\\4\times(x-0,\!3)-0,\!4=2,\!4~~~\Big|+0,\!4\\\\4\times(x-0,\!3)=2,\!8~~~\Big|:4\\\\x-0,\!3=0,7~~~\Big|+0,\!3\\\\\boxed{\bf x=1}$

 

Answer 2

Să se rezolve ecuația:     2·[4·(x-0,3)-0,4] = 4,8

$\it 2\cdot[4\cdot(x-0,3)-0,4]=4,8 \Leftrightarrow 8(x-0,3)-0,8=4,8|_{:8} \Leftrightarrow\\ \\ x-0,3-0,1=0,6 \Leftrightarrow x-0,4=0,6|_{+0,4} \Leftrightarrow x=1$