Question

2,6-2, (3)+1, (6)+(2,3-0,9)

Answer 1

 2,6-2, (3)+1, (6)+(2,3-0,9)
2,6=$\frac{26}{10}$
2,(3)=$\frac{123-12}{90}$=$\frac{111}{90}$
1,(6)= (16-1):9=15:9=5:3=$\frac{5}{3}$
2,6=$\frac{26}{10}$ 
 2,3= $=\frac{23}{10}$
 0,9=$\frac{9}{10}$

$\frac{26}{10}$-$\frac{111}{90}$+$\frac{5}{3}$+( $\frac{23}{10}$-$\frac{9}{10}$)=aducem la numitor comun(=90)
amplificam primul termen cu 9, al doilea cu 1, al treilea  cu 30, si ultimul cu 9
(9×26-111+30×5+14×9):90=(234-111+150+126):90=399:90=$=\frac{399}{90}$