Question

Efectuati :
a.( 3^4)^7÷9^13=
b.(2^9)^2÷4^9=
c.8^24÷16^18=
d.125^9÷25^13=
e.81^15÷27^20=
f.8^13^2÷64^84=
g.3^7^2÷81^12=

Answer 1

$a).(3^4)^7:9^1^3=2^2^8:(3^2)^1^3=3^2^8:3^2^6=3^2^8^-^2^6=3^2=9 \\ b).(2^9)^2:4^9=2^1^8:(2^2)^9=2^1^8:2^1^8=1 \\ c).8^2^4:16^1^8=(2^3)^2^4:(2^4)^1^8=2^7^2:2^7^2=1 \\ d).125^9:25^1^3=(5^3)^9:(5^2)^1^3=5^2^7:5^2^6=5^2^7^-^2^6=5^1=5 \\ e).81^1^5:27^2^0=(3^4)^1^5:(3^3)^2^0=3^6^0:3^6^0=1$
$f). 8^{ 13^{2} } :64^8^4=8^1^6^9:(8^2)^8^4=8^1^6^9:8^1^6^8=8^1^6^9^-^1^6^8=8^1=8 \\ g). 3^{ 7^{2} } :81^1^2=3^4^9:(3^4)^1^2=3^4^9:3^4^8=3^4^9^-^4^8=3^1=3$