Question

2^7:4^3+3^9 înmulțit 27^5:3^20+(3^1 înmulțit 2^4-4^2):2^3=​

Answer 1

$2^7:4^3+3^9 \cdot 27^5:3^{20}+(3^1 \cdot 2^4-4^2):2^3= \\ =2^7:2^6+3^9 \cdot 3^{15}:3^{20}+(3\cdot2^4-2^4):2^3= \\ =2+3^{24}:3^{20}+(3\cdot0):2^3=2+3^{4}+0=2+81=\boxed{\bold{83}}$

Answer 2

Răspuns:

2^7:4^3+3^9 ·27^5:3^20+(3^1 ·2^4-4^2):2^3=​

2⁷:(2²)³+3⁹·(3³)⁵:3²⁰+[3·2⁴-(2²)²]:2³=

2⁷:2⁶+3⁹·3¹⁵:3²⁰+(3·2⁴-2⁴):2³=

2⁷⁻⁶+3⁹⁺¹⁵⁻²⁰+(3·0):2³=

2¹+3⁴+0:2³=2+81+0=83