Question

2^79:(2^32·2^45)+(16+2·154):(3^2·2)^2=? mrs

Answer 1

2^79:(2^32·2^45)+(16+2·154):(3^2·2)^2=
2^79:2^(32+45)+(16+308):(9·2)^2=
2^79:2^77+324:18^2=
2^(79-77)+324:324=
2^2+1=
4+1=5
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