Question

2.Descompuneti in factori,mai intai scotand factorul comun:
d)5x^2-5
e)12ax^2-12a
f )3x^3-12x
g)4x^4-16x^2
h)5x^3-45x
i)x^4-36x^2
j)2x^4-8x^2
k)7x^3-28x
l)x^5-16x

^ = inseama ,,la puterea''

Sunt clasa a7-a,va rog!
Nu inteleg deloc metodele acestea.

Answer 1

d)5(x^2-1)=5(x-1)(x+1)
e)12a(x^2-1)=12a(x-1)(x+1)
f)3x(x^2-4)=3x(x-2)(x+2)
g)4x^2(x^2-4)=4x^2(x-2)(x+2)=(2x)^2(x-2)(x+2)
h)5x(x^2-9)=5x(x-3)(x+3)
i)(x^2-6x)(x^2+6x)
j)2x^2(x^2-4)=2x^2(x-2)(x+2)
k)7x(x^2-4)=7x(x-2)(x+2)
l)x(x^4-16)=x(x^2-4)(x^2+4)=
x(x-2)(x+2)(x^2+4)

Answer 2

poza
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