Question

2. Efectuează aplicând regulile de calcul cu puteri: a) (3/6)⁸ × (1/2)⁴=
b) (5/6)⁶ × (5/6)⁸=
c) (14/10)⁵ × (7/5)⁴=
d) (3/8)¹¹ : (3/8)⁹=
e) (3/9)⁷ : (1/3)⁵=
f) (1/9)⁹ : (1/9)⁸=
g) [(5/8)²]⁰=
h) [(1/2)²]²=
i) [(3/4)²]⁶
j) [(5/3)²]⁵=


va rog repede, dau coroana și am nevoie și de rezolvări, nu doar răspunsuri

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Answer 1

Răspuns:

Explicație pas cu pas:

a) (3/6)⁸ × (1/2)⁴= (1/2)⁸× (1/2)⁴ = (1/2)⁽⁸⁺⁴⁾ = (1/2)¹²

(3/6)⁽³ = (3:3)/(6:3) = 1/2

b) (5/6)⁶ × (5/6)⁸= (5/6)⁽⁶⁺⁸⁾ = (5/6)¹⁴

c) (14/10)⁵ × (7/5)⁴= (7/5)⁵× (7/5)⁴ = (7/5)⁽⁵⁺⁴⁾ = (7/5)⁹

(14/10)⁽² = (14:2)/(10:2) = 7/5

d) (3/8)¹¹ : (3/8)⁹= (3/8)⁽¹¹⁻⁹⁾ = (3/8)²= 3²/8² = 9/64

e) (3/9)⁷ : (1/3)⁵= (1/3)⁷ : (1/3)⁵ = (1/3)⁽⁷⁻⁵⁾ = (1/3)² = 1²/3² = 1/9

(3/9)⁽³ = 1/3

f) (1/9)⁹ : (1/9)⁸= (1/9)⁽⁹⁻⁸⁾ = (1/9)¹ = 1/9

g) [(5/8)²]⁰= (5/8)⁽²ˣ⁰⁾ = (5/8)⁰ = 1

h) [(1/2)²]²= (1/2)⁽²ˣ²⁾ = (1/2)⁴ = 1/2⁴ = 1/16

i) [(3/4)²]⁶ = (3/4)⁽²ˣ⁶⁾ = (3/4)¹²

j) [(5/3)²]⁵= (5/3)⁽²ˣ⁵⁾ = (5/3)¹⁰