Question

2. Impartiri numarul 120 in parti invers proportionale respectiv cu numerele 0,2;0,5;0,25.

Answer 1

a+b+c=120
0,2=2/10=1/5
0,5=5/10=1/2
0,25=25/100=1/4
a*1/5=b*1/2=c*1/4=k
a/5=b/2=c/4=k
a=5k
b=2k
c=4k
5k+4k+2k=120
11k=120
k=120/11
a=5*120/11=600/11
b=2*120/11=240/11
c=4*120/11=480/11

verificare
600/11+240/11+480/11=120-aducem la acelasi numitor
600+240+480=1320
1320=1320