Question

2 la puterea n+3 + 2 la puterea n+1 + 2la puterea n = 88

Answer 1

$2^{n+3}$ + $2^{n+1}$ + $2^{n}$ = 88
Dam factor comul pe $2^{n}$  si rezulta
 $2^{n}$*(2³+2+1)=88
$2^{n}$ * 11=88
$2^{n}$=88:11
$2^{n}$=8
$2^{n}$=$2^{3}$
Deci rezulta ca n=3