Question

2. Să se calculeze:
a) (-2)2 – 1° +(-3)' = - b) (-5)2+(-2)3+ (-1,15= c) (-3)3 = (–7)° +(-2)4 =
d) (-2)3–(-3)2+(-5)2 = e) (-10)2 +4.(-3) 3 => _f) 42: (-2)3+(-1)3 = 31-
g) 02-(-2)3 +50 +(-3)2 = h) (-3)2.4+(-2)) = i) (-2)4 -(-3)2 =
j) (-2)3+(-7)' =
k) -6-(-3)2+(-2)3 = 1) (-4)2+(-62)=(-5) =
m) (-25) +33-(-4)2 = n) (-32)+(-3)2+(-24)= 0) 23-(-2)3 + (-1)100 =
p) (-5)+32-(-44 =
q) 24 +(-2)° – (-3)3 = r)(-3)+(-1) 18-(-7)+34
3. Să se calculeze:
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Odeon
a) (-2); 23:43 +(+1) 9773261-4,677):(-5)+(33):(-4):(-1) =
c) [(-4)2+(-5).3+(-1)^)3 – 3 = Md) [(-15)2:(-3)+(-8)2]:(-11) = 0
e) [(-3)3 +(-5)2]:(-5)2+(-7)2 = f) [(-2)8:3]“: (-2)45:9=

Answer 1

Răspuns:

Explicație pas cu pas:

a) (-2)^2 – 1° +(-3)^1 = 4-1-3=0

b) (-5)^2+(-2)^3+ (-1)^15= 25-8-1=16

c) (-3)^3 - (–7)° +(-2)^4 =-27-1+16=-12      

d) (-2)^3-(-3)^2+(-5)^2 = -8-9+25=8

e) (-10)^2 +4.(-3) ^3 =100+4·(-27)= 100-108=-8

f) 4^2: (-2)^3+(-1)^5 = 16:(-8)-1=-2-1=-3

g) 0^2-(-2)^3 +5^0 +(-3)^2 = 0-(-8)+1+9=8+1+9=18

h) (-3)^2·4+(-2)^5 = 9·4+(-32)=36-32=4

i) (-2)^4 -(-3)^2 =16-9= 7

j) (-2)^3+(-7)^1 =-8-7=-15

k) -6-(-3)^2+(-2)^3 = -6-9-8=-23

l) (-4)^2+(-6)^2-(-5) =16+36+5=57

m) (-2)^5 +3^3-(-4)^2 = -32+27-16= -21

n) (-3)^2+(-3)^2+(-2)^4= 9+9+16= 34

0) 2^3-(-2)^3 + (-1)^100 =8-(-8)+1=8+8+1=17

p) (-5)^0+3^2-(-4)^4 =1+9-256=-246

q) 2^4 +(-2)°- (-3)^3 = 16+1-(-27)=-10

r) (-3)^3+(-1)^18-(-7)^0+3^4= -27+1-1+81=54

3. Să se calculeze:

a) (-2)^3· 2^3:4^3 +(+1)^19 = -8·8:64+1=-1+1=0

b) [-4-(-4)]·(-5) +(-3)·(-4)·(-1) =  [-4+4]·(-5) +12·(-1) =0·(-5) -12 =-12

c) [(-4)^2+(-5)·3+(-1)^4]^3 – 3 = [16-15+1]^3-3=2^3-3=8-3=5

d) [(-15)^2:(-3)+(-8)^2]:(-11) = [225:(-3)+64]:(-11)=(-75+64):(-11)=-11:(-11)=1

e) [(-3)^3 +(-5)^2]·(-5)^2+(-7)^2 =[-27+25]·25+49=(-2)·25+49=-50+49=-1

f) [(-2)8·3]^6: (-2)^45:9= (-2)^48·3^6:(-2)^45:3^2=(-2)^3·3^6:3^2=(-2)^3·3^4= -8·81=-648