Question

2))sa se verifice egalitatea log3 54+(1/7)^-1-log3 2= lg100^5

Answer 1

$log_{3}54+ (\frac{1}{7}) ^{-1}- log_{3}2= log_{3}27+ log_{3}2+7- log_{3}2= \\ =10 \\ lg100^5=5lg100=5*2=10$
deci, 10=10