Question

2. Scrieți folosind o singură putere: a) 13.130.13 = b) 1011': 1011 : 1011 = c) (75) བལ – d) 52.57:51 = e) 41!: 4121. 1681 = f) (3310: 329. (32)2 = g) (11310 . (113)4 : (112,11. 117= h) (211)5: (22)": 4 = 1) (58. 73): (59.74) = 3. ​

Answer 1

$\it a)\ \ 13\cdot130\cdot13=13\cdot13\cdot13\cdot10=13^3\cdot10\\ \\ b) 1011:1011:1011=1:1011=\dfrac{1}{1011}=1011^{-1}\\ \\ c)\ \ incontrolabil,\ \ incoerent\\ \\ d)\ \ 52\cdot57:51$

Answer 2

Răspuns:

Imaginea cu exercitiul...

Explicație pas cu pas:

a) 13^5•13^6•13 = 13^(5+6+1) = 13¹²

b) 1011^9:1011³:1011^0 = 1011^9:1011³:1 = 1011^(9-3) =

= 1011^6

c) (7^5)¹² = 7^60

d) 5²•5^7:5¹ = 5^(2+7-1) = 5^8

e) 4^51:4²¹•1681 = 1681•4^30

f) (3³)^10:3^29•(3²)³ = 3^30:3^29•3^6 = 3^(30-29+6) = 3^7

g) (11²)^10•(11³)⁴:(11²)¹¹•11³ = 11^20•11^20:11^22•11³ =

= 11^-¹¹ = 1/11¹¹

h) (2¹¹)^5:(2²)¹¹:4 = 2^55:2²²:4 = 2³³•1/2² = 2³¹

i) (5^8•7^7):(5^5•7⁴) = (5•35^7):(5•35^4) = 35³

* A fost dificil un pic de a descifra,dar am gasit exercitiul tau (o imagine) ,asa ca totul e corect.