Question

2.Stiind ca a supra 11 = b supra 3 , calculati 7a-2b/3a+5b

Answer 1

$\frac{a}{11}= \frac{b}{3}=k \\ a=11k;b=3k \\ \frac{7a-2b}{3a+5b}= \frac{7*11k-2*3k}{3*11k+5*3k}=\frac{77k-6k}{33k+15k}= \frac{71k}{48k} = \frac{71}{48}$