Question

-2$x^{2}$-5x+3=0
3$x^{2}$-5x+2=0
9$x^{2}$-3x+2=0
$x^{2}$+x+1=0
-$x^{2}$+16=0
-$x^{2}$+2x=0
Ecuatia de gradul 2.

Answer 1

Răspuns:

Explicație pas cu pas:

16-x²=0...(4-x) (4+x) =0...x1,2=±4

2x-x²=0....x(2-x) =0...x1=0; x2=2

3x²-5x+2=0

x1,2=(5±√(25-24))/6= (5±1)/6...x1=4/6=2/3; x2=1

x²+x+1=0...x1.2∉R pt gimnaziu

x1,.2= (-1±i√3)/2 pt liceu