Question

2(x+1)^2-(x-2)(x+2)=27

Answer 1

$2 {(x + 1)}^{2} - (x - 2)(x + 2) = 27$

$2( {x}^{2} + 2x + 1) - ( {x}^{2} - 4) = 27$

$2 {x}^{2} + 4x + 2 - {x}^{2} + 4 = 27$

$2 {x}^{2} - {x}^{2} + 4x + 2 + 4 - 27 = 0$

${x}^{2} + 4x - 21 = 0$

${x}^{2} + 7x - 3x - 21 = 0$

$x(x + 7) - 3(x + 7) = 0$

$(x + 7)(x - 3) = 0$

$= > x + 7 = 0 = > x_{1} = - 7$

$= > x - 3 = 0 = > x_{2} = 3$

Answer 2

Sper ca te-am ajutat !