Question

2*(x+ radical din 2 - radical din 5) + 3 = x*(radical din 5 - radical din 2)

Answer 1

2x+4√2-2√5+3=√5x-√2x

4√2-2√5+3=√5x-√2x-2x

4√2-2√5+3=x(√5-√2-2)

x=4√2-2√5+3/√5-√2-2