Question

200 grame Mg(magneziu) reactioneaza cu O(oxigen). Ce cantitate de oxid de Mg se obtine din reactie si cati moli?

Answer 1

2Mg+$O _{2}$=2MgO

$M _{MgO}$= 24+16=40g/mol
$m_{MgO}$=(200*2*40)/(24*2)=333,(3)g
$n_{MgO}=333,(3)/40=8,(3)moli$