Question

200g oxid de cupru cu 80% puritate reactioneaza cu solutie de acid azotic, randamentul reactiei fiind de 90%. Masa de sare formata este?

Answer 1

p=m pur/m impur*100 => mpur=80*200/100=160g CuO

CuO + 2HNO3 -> Cu(NO3)2 + H2O

MCuO=80g/mol

MCu(NO3)2=188g/mol

80g CuO...........................188g Cu(NO3)2
160g CuO........................x=376g Cu(NO3)2 (mt)

n(eta) = mp/mt*100 => mp=n*mt/100=90*376/100=338,4 Cu(NO3)2 [sare]