Question

2¹⁹⁹⁴+2¹⁹⁹³-6×2¹⁹⁹²=??? dau coroana​

Answer 1

Răspuns

${2}^{1994} + {2}^{1993} - 6 \times {2}^{1992}$

${2}^{1994} + {2}^{1993} - 3 \times 2 \times {2}^{1992}$

${2}^{1994} + {2}^{1993} - 3 \times {2}^{1993}$

$(2 + 1 - 3) \times {2}^{1993}$

$0 \times {2}^{1993}$

$0$

Sper că te-am ajutat:)