Question

22.treceti in baza 10 in baza 2 numarul natural a=[(5×5^2×5^3)^4 :125^7 -5^2]^3:25^3. ​

Answer 1

Răspuns:

a=64 =1000000₂

Explicație pas cu pas:

a=[(5×5²×5³)⁴:125⁷-5²]³:25³

a=[(5⁶)⁴:(5³)⁷-5²]³:(5²)³

a=(5²⁴:5²¹-5²)³:5⁶

a=(5³-5²)³:5⁶

a=(125-25)³:5⁶

a=100³:5⁶

a=[(2²×5²)³:5⁶

a=2⁶×5⁶:5⁶

a=2⁶

a=64

64:2=32 rest 0

32:2=16 rest 0

16:2=8 rest 0

8:2=4 rest 0

4:2=2 rest 0

2:2=1 rest 0

64 ₁₀=1000000₂

Proba : 1000000=1×2⁶+0×2⁵+0×2⁴+0×2³+0×2²+0×2+0×2*0=2⁶=64

Multa bafta!