Question

24 supra radical 3 + 30 supra 5 radical 3 - 42 supra 7radical 3+ 26 supra radical 3

Answer 1

$\frac{24}{ \sqrt{3} } + \frac{30}{5 \sqrt{3} } - \frac{42}{7 \sqrt{3} } + \frac{26}{ \sqrt{3} } = 8 \sqrt{3} + \frac{6}{ \sqrt{3} } - \frac{6}{ \sqrt{3} } + \frac{26 \sqrt{3} }{3} = 8 \sqrt{3} + 2 \sqrt{3} - 2 \sqrt{3} + \frac{26 \sqrt{3} }{3} = \frac{3 \times 8 \sqrt{3} }{3 \times 1} + \frac{26}{ \sqrt{3} } = \frac{24 \sqrt{3} }{3} + \frac{26 \sqrt{3} }{3} = \frac{24 \sqrt{3} + 26 \sqrt{3} }{3} = \frac{50 \sqrt{3} }{3}$