Question

25-15÷{1+3×[(57-60÷4×2)÷3]-230÷10}

Answer 1

$25 - 15 \div (1 + 3 \times ((57 - 60 \div 4 \times 2) \div 3) - 230 \div 10) \\ 25- 15 \div (1 + 3 \times (27 \div 3) - 230 \div 10) \\ 25 - 15 \div (1 + 3 \times 9) - 230 \div 10\\25 - 15 \div 28 - 230 \div 10 \\ 25 - 0.53 - 23 \\ 24.47 - 23 \\ 1.47$